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Guest repliedOk great I think I've got it now. All 3 stators to the R/R, 2x brown positives to red positives, one black R/R neg to battery, one to SPG on frame screw.
The un-used headlight lead- just leave it dangling/tape it?
My bike already had a ground lead from battery (-) to R/R frame screw, so I've got that covered. Probably something TKent did, since it doesn't look original.
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This is described in various locations under Single Point Ground (SPG). The idea is that all ground currents are collected into a SPG as close to the R/R(-) as possible. That is why the R/R mounting bolt is convenient.Originally posted by bwanna View PostAs mentioned. It's a good technique to connect the RR neg directly to the Battery Neg terminal AND to the frame ground. If you rely on a second frame-battery neg connection and THAT second connection is not sound, the RR may not function to full output correctly.
The three (16 AWG recommended) wires that need to come to this SPG are:
- Factory Harness ring lug ground (B/W)
- Battery (-)
- Frame ground
The output of the SPG is the 14 awg wire to R/R(-). Keep this wire as short as possible (less than 1 ft)
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Guest repliedAs mentioned. It's a good technique to connect the RR neg directly to the Battery Neg terminal AND to the frame ground. If you rely on a second frame-battery neg connection and THAT second connection is not sound, the RR may not function to full output correctly.
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Guest repliedThe 3 stator wires go to the three input wires on the RR. IF there are two voltage wires then tie them together, and the same if there are two ground wires then tie them together. The 775 should have two receptacles, one with 3 contacts (for stator wires) and one with 2 contacts (Pos and Neg)Originally posted by StratJeff View Post@posplayr
Ok, I've read through this entire thread (and a handful of others), but being electrically ignorant, I wanted to make sure I've got the wiring correct from my SH-775 swap.
There are 3 wires from the Stator- two originally went to the R/R, but the third loops back into the harness and goes *somewhere*. I assumed this is fused? How/where do I use that third line with the third lead from the SH775?
There are the 2 positive wires, which I'll mate to the 2 positive leads on the SH775. This leaves 2 negative leads on the SH775- does one go to the battery, and one to a frame ground?
Sorry to be a pain, but I need my hand held with this stuff
Cheers!
Make sure your have a fuse between the voltage and the battery positive.
Tie ground to the battery neg and tie also you the frame. Don't rely on just tying the RR neg to the frame.. You want to also connect to battery
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Look at the attached pic of a SH-775.....The three yellow wires connect directly to your stator: the red wire connects to same place that your original red wire from r/r connected to. The black wire connects to a good ground- hopefully this good ground has good contact with battery negative.Attached Files
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Guest replied@posplayr
Ok, I've read through this entire thread (and a handful of others), but being electrically ignorant, I wanted to make sure I've got the wiring correct from my SH-775 swap.
There are 3 wires from the Stator- two originally went to the R/R, but the third loops back into the harness and goes *somewhere*. I assumed this is fused? How/where do I use that third line with the third lead from the SH775?
There are the 2 positive wires, which I'll mate to the 2 positive leads on the SH775. This leaves 2 negative leads on the SH775- does one go to the battery, and one to a frame ground?
Sorry to be a pain, but I need my hand held with this stuff
Cheers!
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keepandshare turned my account back on
RR_Tutorial.pdf -- June 5, 2012 11:34 pm -- 837k
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SSR_vs_FH012AA.pdf -- May 31, 2012 10:20 pm -...
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Your analogy does not treat the source and load in the same way as mine. Imagine source and load in series. When you short the source (the leads going to the load) the power delivered to the load goes to zero, the source current is only limited by the power available and the source resistance. Apply that to your analogy and you will see that your analogy is something else.Originally posted by Gorminrider View Postnot to worry, Pos. not on "ignore".
I just can't filter through all these factoids... what I said; to wit-"the stator is not grounded" reply?)
...I was responding to Nessisms post. It just seems to add to what is shunting hysteria -I call it that because it implies the misconception that when your shunt regulator is shunting, it is as though the stator is a big hot lightbulb made of tungsten. I suggest it is No more true than your housewiring is an element of your oven! how could you cook if your wiring all got as hot as the element? and what power are you using? It goes back to the power company through your meter-electricity doesn't "go","flow" or "move" anyways but that's a digression.
I assume you have just arrived and not had much time to look around; I'll help.Originally posted by Gorminrider View PostI am still looking for a representation that simply links a "series versus shunt" to stator burnouts. I am not saying it is not so, but unfortunately, it is apparently beyond my grasp here.
Maybe 3-5 years down the road when people stop chortling over their brand new stators and series regulators.....then I'll see how those stators are doing.
There is an explanation of SHUNT v.s SERIES posted over 5 years ago. My keepandshare account went dormant 2 days ago.
You really love to waste my time right? I'm using lowest resistance for minimum room temperature and you go quoting 2 ohms? You obviously are backpedaling through a cloud of confusion.Originally posted by Gorminrider View Post...but here and now, suggesting that there's 2 ohms through any two stator leads my coils is not helping. I have 3 stators. none show anywhere near 2 ohms and never did before rewinding. http://circuitcalculator.com/wordpre...er-calculator/
35' of 18ga is .0.223ohm @20C as an estimate...can't recall if I got it all on! Still, at 100C I see...0.294ohms. hmmm-I suppose you can consult your own sources but the suzuki wire leads attached to stator windings have PVC coating good to 100C , so I call it academic...
The data on stator current has been posted for well over 6 years. Google itOriginally posted by Gorminrider View PostThe proportion that is "shunted" or not may be big news at the regulator - though a decent shunt regulator in a cared-for system has no problem- but even if it is true, giving or taking 30 watts heat seems pretty small potatoes at the stator, compared to the 30-100 hp engine surrounding it.
, well that would depend on several factors wire size, length...but where there's a mere 14vdc @15 amps available, it may not be the problem you suggest. and since a shunt is implied why not include it to make a better model...in which case, I am guessing the shunt will be the greatest resistor in this scenario and it will be the hottest thing with a high voltage drop. etcetcetc
SHUNT_vs_SERIES_RR_Compare_Tutorial
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not to worry, Pos. not on "ignore".
I just can't filter through all these factoids... what I said; to wit-"the stator is not grounded" reply?)A SHUNT regulator is the only type that "grounds" the stator. I put "grounds" in parenthesis as while the stator is grounded it is also shorted leg to leg so there is no actual current flow to chassis ground or anything but a back through the 3 phase stator circuit. It is also not a perfect ground as the shorts generally occur through an SCR. through
...I was responding to Nessisms post. It just seems to add to what is shunting hysteria -I call it that because it implies the misconception that when your shunt regulator is shunting, it is as though the stator is a big hot lightbulb made of tungsten. I suggest it is No more true than your housewiring is an element of your oven! how could you cook if your wiring all got as hot as the element? and what power are you using? It goes back to the power company through your meter-electricity doesn't "go","flow" or "move" anyways but that's a digression.
I am still looking for a representation that simply links a "series versus shunt" to stator burnouts. I am not saying it is not so, but unfortunately, it is apparently beyond my grasp here.
Maybe 3-5 years down the road when people stop chortling over their brand new stators and series regulators.....then I'll see how those stators are doing.
...but here and now, suggesting that there's 2 ohms through any two stator leads my coils is not helping. I have 3 stators. none show anywhere near 2 ohms and never did before rewinding. http://circuitcalculator.com/wordpre...er-calculator/
35' of 18ga is .0.223ohm @20C as an estimate...can't recall if I got it all on! Still, at 100C I see...0.294ohms. hmmm-I suppose you can consult your own sources but the suzuki wire leads attached to stator windings have PVC coating good to 100C , so I call it academic...
The proportion that is "shunted" or not may be big news at the regulator - though a decent shunt regulator in a cared-for system has no problem- but even if it is true, giving or taking 30 watts heat seems pretty small potatoes at the stator, compared to the 30-100 hp engine surrounding it.
, well that would depend on several factors wire size, length...but where there's a mere 14vdc @15 amps available, it may not be the problem you suggest. and since a shunt is implied why not include it to make a better model...in which case, I am guessing the shunt will be the greatest resistor in this scenario and it will be the hottest thing with a high voltage drop. etcetcetcIf I connect the ends to a light bulb I could get it to light up but if I short the bulb/load they way a shunt r/r does, I could end up melting the wire.Last edited by Gorminrider; 12-31-2015, 04:28 PM.
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The light bulb explanation is easy to understand. I like to describe dimming the lights in the method of a shunt R/R as using a pair of screwdrivers to short a wall outlet to dim the ceiling mounted lights. Of course the lights dim and the house wiring would also melt if it were not fused.Originally posted by Brendan W View PostThe way I see it there is a battery, filaments and other things that require output voltage from the r/r be limited. A shunt r/r does this by providing a low impedance bypass of the load and then lets the phases deal with the diverted energy any way they can.
I look at it like a long wire with a varying magnetic field in the middle. If the ends are not joined no current flows. If I connect the ends to a light bulb I could get it to light up but if I short the bulb/load they way a shunt r/r does, I could end up melting the wire.
The Series R/R simply flips the light switch on and off fast enough and at the appropriate duty cycle to get the light level desired.
The analogy makes it clear that the SHUNT v.s. SERIES methods are as different as "light and dark"
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The way I see it there is a battery, filaments and other things that require output voltage from the r/r be limited. A shunt r/r does this by providing a low impedance bypass of the load and then lets the phases deal with the diverted energy any way they can.
I look at it like a long wire with a varying magnetic field in the middle. If the ends are not joined no current flows. If I connect the ends to a light bulb I could get it to light up but if I short the bulb/load they way a shunt r/r does, I could end up melting the wire.
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This group of statements are technically no more accurate than Ed's assuming it is understood that he is only describing a Shunt R/R. In fact they would appear on the surface to even be contradictory (".. it is grounded,...it has no connection to ground..."Originally posted by Gorminrider View Postit is not. It is grounded through regulator. The stator has no connection to ground.
)
A SHUNT regulator is the only type that "grounds" the stator. I put "grounds" in parenthesis as while the stator is grounded it is also shorted leg to leg so there is no actual current flow to chassis ground or anything but a back through the 3 phase stator circuit. It is also not a perfect ground as the shorts generally occur through an SCR. through
While I agree with the formula(I have been using it for the last several posts) you need to derate for power factor. I guestimated 0.70.Originally posted by Gorminrider View PostSIMPLY put, the only power consumed by stator is the current passing through it (squared) times the windings resistance( <.3 ohms) and that's always ,< 40 watts with stock loads (signals, lights,coils) whatever R/R you have. Using ALL of your stator's output on the bike somewhere would make this about 30 watts more... <70 watts.
I also agree with the fact that it applies to any R/R, but I can not disagree with the rest as the current flow between SERIES and SHUNT R/R is totally different which has been discussed at length. (You must have me on ignore). I published the data on direct measurements back in 2010. I was probably on ignore back then also I suppose as this data has been widely referenced on the web since that time.
Current flow is not a question; it has been documented. But to use the formula you mention P=I^2xR you need to know R(in addition to power factor). So my discussion above attempts to bound the answer to that question.
There is no Spec in the Suzuki manuals I looked at the 1100E) for stator resistance. I don't have a stator handy to measure so I relied on the Stator pages which lists between 0.5 and 2.0 ohms. It can be safely assumed that the lower number is a room temperature stone cold number. To state the obvious the lowest possible number is the shortest thickest wire stator at lowest temperature. We can infer that the wide range quoted between 0.5 all the way up to 2.0 ohms might be owing to both manufacturer to manufacturer variations as well as temperature dependency. Temperature dependence would account for a large portion of this.
In the calculation I provided the rise in resistance of a room temp 0.5 ohm stator will be 0.86 ohms at 400 degF (the temperature required to burn powered coated epoxy coverings).
Follow my measurements (you have to get off ignore) and you get a whole different number exceeding 400 watts.Last edited by posplayr; 12-31-2015, 02:27 PM.
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it is not. It is grounded through regulator. The stator has no connection to ground.because power not consumed by the system is excess and shunted back to the stator
SIMPLY put, the only power consumed by stator is the current passing through it (squared) times the windings resistance( <.3 ohms) and that's always ,< 40 watts with stock loads (signals, lights,coils) whatever R/R you have. Using ALL of your stator's output on the bike somewhere would make this about 30 watts more... <70 watts.
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It would seem your conclusion was induced from circuitous reasoning.Originally posted by Nessism View PostThe total amount of power the generator produces is important because power not consumed by the system is excess and shunted back to the stator. And this has everything to do with the discussion at hand.
Fact of the matter Jim you are overestimating how much power the generator produces and therefore how much excess is shunted back. Either that or your Electrosport stator IS significantly boosting power produced in your changing system because most UJM charging systems were making mid 200's watts.
I know I made a couple of punnies
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