My 1100E has an intake velocity of ~ 22m/s @ 9000rpm (assuming steady flow, 100% volumetric efficiency and 34mm carb bores). Because the total velocity vector will be the square root of the sum of the squares you will need an unobtainable amount of swirl to significantly lower the pressure beyond what it achieves without the swirl. To achieve a 1% increase in the total velocity over the 22m/s you need a tangential velocity (the swirl velocity) of 3.12m/s. In a 34mm bore that equates to a swirl of 5500RPM. And only the very outer portion of the bore achieves that much velocity increase, the rest drops off with the radius it is swirling at from the bore centerline.
Mark
OK I refreshed my memory (it was blearaly correct).
An ideal (potential flow) vortex has a velocity profiles of 1/R (R is distance from the center) so even in practice it gets pretty high velocity (lowering the pressure) right at the center. V can't go to infinity because viscosity starts to come into play.
Vortexes are a fundamental part of fluid dynamics and is what is used to explain circulation which is what generates Lift.
Those aircraft wing tip vortices have a lot of energy in them just generated by the spanwise flow, rounding the tips of the wings.
