Another way to look at it is that some of the reduced voltage loss simply gets "eaten up in the stator" instead of the diodes/fets.
I suspect that the OEMs are using the fet regulators mainly because they move a lot of the heat generated during shunting "away from the R/R to the stator", which is better able to handle it.
Martin
with voltages regulated to the same value,
plus considering the stator has a fixed resistance and the impedance of the stator should be the same with the "differences in resistance" between the scr and fet r/r's.
would you please explain why?, so I may absorb your answer. (my educational value only)
***added thoughts*** the only factor that would change the power dissipated in the stator would be, if the capacitance of the changed device (R/R) was different from the OEM values, and that would be true with the Honda and FET R/R.
the series load formed by the fixed loads (lights, devices) and the battery in parallel, would decrease as the battery charged up because of it's increased internal resistance nearing a full charge. therefore limiting the current in the circuit.
if the above is correct, that would make the FET style R/R the better choice in R/R's.
I only have a bit of time during lunch, so I'm not sure I can address all of it today.
First, just to be clear, my two paras you quoted were meant to apply to different aspects of the R/R operation.
The first was primarily to explain why the FET may have less advantage at Low RPM than it would seem to (although I guess it applies during shunting too)
The second was to explain why I suspect the OEMs use the FET type (apparently especially for high current ones)
Ok, let me try to explain my second para better first.
I know how the SCR type work, but prior to this thread have not seen any info on the FET type.
I assume Posplayr's description of operation in post 10 to be correct. If not, then none of this holds ...

(As an aside ... it would be possible to run an FET type in a manner where it doesn't shunt, but instead disconnects the stator leads for a portion of the cycle.
This would reduce currents (and heat) by a LOT. But it would have its own issues (the stator leads would go up to 120 volts at times for instance))
But anyway ...
The R/R has to get rid of any heat it generates.
This heat is equal to V*I losses in the R/R.
During those parts of a cycle where the R/R is rectifying (but not shunting) V will be the "diode" losses.
Where an actual diode is acting as the diode (top and bottom in a standard R/R or the top diode in a FET R/R) this V will be .7 to 1.4 Volts.
Where a FET is acting as the "diode" (the bottom of a FET R/R) this V will be .3 volts or less.
The currents will be similar, perhaps a bit higher for FET type.
(if the current is higher, the R/R will compensate by shunting a bit higher % of the cycle)
So the total loss of a standard R/R is 1.4 to 2.8 volts
The total loss of a FET type is 1.0 to 1.7 volts
So the heat will be significantly less for a FET R/R for this portion of the cycle.
During those parts of a cycle where the R/R is shunting, V loss will be:
For a standard R/R one diode drop (0.7-1.4 volts) plus 1 SCR drop (0.7-1.4 volts) total 1.4 to 2.8 volts
For a FET R/R during shunting it would be 2 FET drops (approx 0.3 volts each) total .6 volts or less
Depending on the stator's V-I charachteristics, current will be slightly to a good bit more.
So the heat generated during shunting is 1/4 to 1/2 as much as a non-FET.
Because the current will likely go up a bit for a FET type, the losses (and heat) in the stator will probably increase a bit.
So the R/R runs a LOT cooler, but the stator a bit higher ... but the stator has an oil bath to help carry away the heat ...
I probably won't be able to get to the other part till mon if you still want me to.