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Ohms law is V=IR
Relating that to the pictured analogy, the voltage push (or pressure) required to overcome a given ohm resistance is in proportion to the amount of current in amp (flow) you want.
For a given R ohms, Current increases with voltage.
All of these forms are the same law; if you know the value any two, you can solve for the third.
V=I*R
I=V/R
R=V/I
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In the case of your low battery
I=V/R (assume R is constant)
A lower V gives a lower I.
What does that have to do with heat? heat is the accumulation of energy converted to heat. Like if you burn a wooden stick, the energy in the stick turns to heat, current pushed through R gives off heat in a similar way. In fact this is considered an ideal conversion of energy to heat.
Electrical power is given by P = I*V (in words the voltage times the current is electrical power). Substitution for i or V we get two different forms
P = IV=I^2*R = V^2/R
In P=I^2*R we see power is proportional to resistance R for any given I^2.
Thanks for taking the time! I went outside and found the battery fully charged by the tender, so proceeded to do the quick test. The loose negative battery connection was probably causing the no-start situation I experienced after a 50 mile ride yesterday. The battery is about 3 years old (Yuasa), so I'll replace it regardless. Here are some numbers..
Key Off = 13.15
Key On = 12.33
Idle =12.66
2500 rpm (approx) = 12.80
5000 rpm (approx) = 12.89
Key Off =12.89.
Paid attention to the r/r bullet connectors... the wires do get hotter on the side after the connectors (away from r/r), but not super hot where they cannot be handled etc. The connectors certainly need to be refreshed.
Edit: Took another reading about 15 mins after shut down (no battery tender applied) and battery reads 12.66.
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