M
Matchless
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Pete check your PM!
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Supply voltage: 12v ~ 13v
Coil "on" when G > 1.64v
Coil "off" when G < 1.43v ~1.44v
Pete check your PM!
this bit leaps out at me,
HTML:Supply voltage: 12v ~ 13v Coil "on" when G > 1.64v Coil "off" when G < 1.43v ~1.44v
I think it possible pick up dosnt give quite a high enough pulse to switch it. thus why not firing every time.
Also worth remembering amplitude of the pulse will vary with the speed the of the cranking. (try kicking harder pete)
john


Pete,
The resistor R1 is to limit the current and should not be changed. The bias voltage is determined by the drop across each diode. In the GS1000 method we added another 10 or 15 ohm resistor R2 to lift the bias voltage to 1.4V. If you do that, can you actually measure the 1.2V or 1.4V by which the ground has been lifted? You need to be sure that is actually happening. The pulse is then closer to the HEI triggering point.
You may find that if you go too high with the bias voltage the HEI may just stay on. If this is the case, have a look at using a transistor to drive the HEI, like Lou used in the last part of the notes for a points configuration HEI. The transistor is then triggered by the much smaller pulse from the pickup and it in turn generates a larger pulse to trigger the HEI. In fact just a little pulse amplifier.
You can find Lou here: http://www.kzrider.com/forum/4-electrical/439171-pick-up-coil-question#439185
His handle is louhvx on that forum. He may help you or give some advice.
What is voltage drop across the diodes? you could always substitute different diodes with a different drop.
A wise choice.I think I'm going to need to take John up on his offer of the use of his scope...


Don,
You can download a factory suzuki manual from basscliff, although he may not have the 450 version, but for the purpose of how the ignition works I'm pretty certain they are all the same.
I checked the 550 manual and it says the signal generators make an AC current (the rotor is a magnetic) which then triggers the ignitor. I don't know how the HEI operates but it's hard to imaging it operates differently (but what do I know).
Pete,
If the input of the HEI module requires a input that's 180 degrees out of phase from the stock system and you need voltage gain as well, how about making an inverting amplifier out of an Op amp?
http://www.technologystudent.com/elec1/opamp2.htm
http://www.wisc-online.com/objects/ViewObject.aspx?ID=SSE2903
Pete,
Dale has a very good suggestion with using an op-amp and it is even easier than a transistor seeing you have a breadboard. If I can suggest:
1) Test what polarity with the 1.5v battery fires the HEI, that should give you an idea as to whether it needs the positive going or negative going part of the pulse.
2)You need to swing the motor with the starter to measure the amplitude of the pulse from the pickup. By hand is too slow. Or pull the pickups off the bike and swing the magnet past it fast by hand.
3) The pulse on top of the "bias" voltage should lift the pulse into the range of 1.45 to 1.65V to fire the HEI. (I am using the figures you quoted)
4) The bias voltage must stay under 1.37V to allow the HEI to switch off properly between pulses otherwise you may experience "ghost" sparks which can be seen with a timing light.
5) The op-amp power feed should have some sort of regulation, zener or VR and smoothing capacitors for the final product before installing it on the bike. For testing a battery not under charge may not need this.
Now that you have a scope handy you can actually see what is happening or not happening!
Once you solve this problem, you are going to help many people as the GS450 ignitors seem to fail quite easily.